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Fix isNameOf...() functions for case of string contains whitespaces only
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@ -27,6 +27,9 @@ string simplifyString( string const & str )
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while( endPos && Utf8::isspace( str[ endPos - 1 ] ) )
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--endPos;
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if( endPos <= beginPos )
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return string();
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result.reserve( endPos - beginPos );
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while( beginPos < endPos )
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